3x^2+60x-100=0

Solution for 3x^2+60x-100=0 equation:

3x^2+60x-100=0

a = 3; b = 60; c = -100;
Δ = b2-4ac
Δ = 602-4·3·(-100)
Δ = 4800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4800}=\sqrt{1600*3}=\sqrt{1600}*\sqrt{3}=40\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-40\sqrt{3}}{2*3}=\frac{-60-40\sqrt{3}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+40\sqrt{3}}{2*3}=\frac{-60+40\sqrt{3}}{6}
$